Ok post #4 you implied PE wasn't just the weight like I originally said, so the only other option is both(sure as well can't just be the cart).
Lol...sorry but you're not helping much... it's been a long day, tired, was justing looking for a quick answer. nvm, I'll just ask my teacher tomorrow.
Ok so only the cart is moving. So PE both and KE just cart mass?
But I know that's wrong because then PE ends up around about 90 times bigger than KE.
What is it then? will you please kindly just cut to the chase?
Well for the PE side I just used the mass of the weight
for the KE side, I got both masses.
I already did all the calculatiosn etc, just looking for some quick confirmation or where I went wrong.
Ok, there is a cart on a table(very little friction) with a string attached to it. The cart and the string goes over a pulley at the edge of the table, and has a weight hanging down the side of the table. So when you let go of the cart, it will accelerate until the cart hits the floor, then go...
My work so far...
KE(1) + 0.5(k)(x)^2 = Work (gravity) + PE(2)
where 1 is the bottom of the incline plane and 2 is the top. and 0.05m is the distance between the 2 points. (using bottom of incline plane as reference point)
I found the hight at 0.05m up the incline to be 0.0087m and the x...
Car with mass of 1500kg, accelerates from 0 to 18 uniformly in 12 sec. Air drag is 400 N. Find the inst. Power output of engine at t = 12s. just before car stops accelerating...
Well I found the average power to be 23850 w, but how would you get the instantaneous?
Yeah, I already know all the things talked about above from all the other projectile motion questions I did... I made some progress, but can someone please tell me what the answer would be? So atleast I would know if I solved it right or not...
A really tough question
well.. for me atleast
Any hints? I'm still trying to figure out where to start :cry:
EDIT: *though = tough
...can someone please tell me what the answer would be? So atleast I would know if I solved it right or not.
I thought that was surprisingly easy, just use (sin30)*60*4, but I ended up with 207.84m, but the answer book said it was 212m? What did I do wrong?
I figured out the vertical component of the initial speed to be 28 m/s, but how can you get the horizontal? I think you may be able to get the...
I was doing some momentum questions. There some that goes like "a man dives into water, and comes to a stop x seconds after reaching water, what force did the water act on him" or "stuntman jumps onto a mattress, matress compressed down x meters before he is brought to rest, what force did the...
I managed to do most of the question(whether it's wrong or right), Figured out friction was 7.23N, and the box slides down with 9.64 N if the force is not applied... But what I'm confused on is, how do you use a Y component to cancel out the x component? (I mean if you draw a coordinate plane...
I tried to work it out but doesn't that just restate the fact that walking is 2/3 times slower than escalator? Which you've already concluded from the 60 sec to 90 sec ratio...
I spend 2 hours this evening trying to do these problems, but for these 2, I couldn't manage to even draw a proper diagram for :frown: ... For the last question, I tried to draw it, but the resultant vector wasn't matching with the answer, so obviously it was wrong...
I was able to figure out part c (by using -9.8 and the acceleration forumla), comes out to 2.55s, rounded to 2.6s. No problems there.
For part a, I used Velocity average = delta d / delta t
(25+0)/2 = delta d / (2.6*2) I did get the right answer, but I don't fully understand the conceptual...
Oh for Number 2a), I found acceleration to be 22m/s^2. The answer is 22N/kg, so maybe you assume she's dropping at maximum angle 90. a = g sin(theta), sin would be 1, so gravity comes out to be 22? I don't know... Just a crazy guess.
1. A person throws a ball upwards with a speed of 15 m/s, calc:
a) the time to the top of the trajectory (1.53s)
b) time the ball is in flight (3.06s)
c) max height of the ball (11.5m)
2. An astronaut is repairing top of her craft while docked on a strange new planet. ( :rolleyes: ) She...
Well we are forbiden to use those equations, only the simple ones.
And I did plug it in, the variables simpled canceled out for me. I tried 6 = (2x-x)/t
t=(2x-x)/6 so i set that equal to (2x-x)/6 = 10/1.5x... (I'm still working at the question though...)
Well there's like 20 questions in total, this is the only one out of the bunch I didn't get. I tried to average velocity formula
like...
I found acceleration is 6 m/s^2, by using 36N/6kg
v average = (x + 2x)/2 So velocity average is 1.5x, and I put it back into the velocity average = d...
is there a way to solve it w/o d= Vi(t) + .5a(t^2)?
Our teacher forbid us to use it. We can only use the basic ones like a=delta v/ delta t, v average = delta d / delta t.
A sled of 6.0 kg mass is moving along a smooth, horizontal ice surface with a velocity of X. A force of 36N is applied to the sled in its direction of motion, increasing its velocity to 2X while it moves 10m. Find the sled's original velocity, x. And the length of time that the force acted...
An electron has a mass of 9.1*10^-31 kg. Between the electrodes of a cathode-ray tube, it moves a distance of 4.0mm, accelerated by a net electrical force of 5.6*10^-15 N. Assuming it started by rest, find it's acceleration and final velocity.
I found the acceleration to be 6.15*10^15 m/s^2...
Ok we did a force vs acceleration graph in class, and got an equation from it(couldnt use Y and X for the equation). The question is explain why the equation is F=ma in disguise. Obviously it is, like force is the y, slope is the mass etc, but how can I actually explain it is?
There's two problems I can't seem to figure out...
I sort of got the answer, except I used m as 28 instead of 27. So my question is why are you suppose to use m as 27 to multiply instead of 28? Also What do they mean by incident normally, is it like striking the glass at a right angel?
and...
That is what the question said... I did omit the diagram, but it's just a simple and plain wave with a line through it, no measurements, no info of any kind.
A series of wave crests, all of which will pass a point in 0.50s, find wavelength (cm), frequency, and velocity
The answers are 3.8cm, 6.0 Hz and 23 cm/s...
Can someone explain how to get those answers? I did arrive at an answer, but they weren't right :(.
I'm doing the quantum theory in my class, and on the orbitals chapter... And a question in my book says "what are 'unpaired electrons'"? Do they mean what they are called? And even so, I don't know the answer :confused:
I do see the pattern, it's doubled... but can someone just PLEASE just answer it straight forward, there's a whole bunch of those questions to do and I'm really really really confused right now...
And as for the scale, the graph was rather tiny but I know for sure mine is a lot wider than it...
f(x)=(1/8)x^3
I think because the 1/8 is less than 1, therefore it's wider, but if it's greater than 1, it's narrower right? I tried to graph it, but looks like mine was way to wide, and not matching what the answer book had... Can someone explain and sketch it for me? Thanks!