Search results for query: *

wouldn't plotting the actual graph help??

the thing is that I'm not familiar with de moivre's theorem. i guess we did only basic complex numbers at school. i came across this question on a past paper from another examination board. it's prolly not in our syllabus. thnks

thanks futurebird

and the question continues, i can't find that too. given that \omega is one of the non real roots, show that 1 + \omega + \omega^{2} = 0

Homework Statement find the three roots of z^{3} = 1, giving non real roots in the form of e^{i\theta}, where -\pi<\theta\leq\pi Homework Equations z = re^{i\theta} The Attempt at a Solution i kno that one of the roots is 1, an the other two form a conjugate pair. i can't find them.