Read about dirac biliniars | 1 Discussions | Page 1

  1. hamad12a

    I How Peskin & Schroeder simplified this horrible product of bilinears?

    P&S had calculated this expression almost explicitly, except that I didn't find a way to exchange the $$\nu \lambda$$ indices, but I'm sure the below identity is used, $$ \begin{aligned}\left(\overline{u}_{1 L} \overline{\sigma}^{\mu} \sigma^{\nu} \overline{\sigma}^{\lambda} u_{2...
Top