# Strings pulleys Definition and 6 Discussions

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1. ### Find the acceleration of the masses

I solved this problem by assuming that the acceleration ##a## is the same on the both the masses M and 2M but then answers were wrong, but if the acceleration of the mass 2M is considered as ##a/2## then I get the right answers, but I don't how exactly acceleration is getting halved for mass 2M...
2. ### I Why doesn't the released mass m2 on pulley have higher acceleration?

Consider the pulley in the attached image to be frictionless. (a) If m2 is released, what will its acceleration be? My question is why wouldn't m2's acceleration be greater if released rather than attached to the string because m2 released is no longer subject to the string's upward force tension?
3. ### Three mass Atwood Machine

In the cable-pulley system shown here, block A is moving upwards at a speed of 5m/s and block C is moving downwards at a speed of 2.5m/s. What is the speed of block B? (See attached picture) This seems easy, I just want to make sure I'm not crazy. If mass B moves downward some distance d...
4. ### Strings and Atwood Machines

Homework Statement When talking about an Atwood machine, a student states: Is the student correct or incorrect? Why? Homework Equations Tension = mg + ma The Attempt at a Solution This is how it is making sense in my mind, but correct me if I'm wrong. I am thinking that the student is...
5. ### Find mass of cylinder (rotational motion question)

Homework Statement A light string is wrapped around a solid cylinder and a 300 g mass hangs from the free end of the string, as shown. When released, the mass falls a distance 54 cm in 3.0 s. a. Draw free-body diagrams for the block and the cylinder. b. Calculate the tension in the string...
6. ### A string over a pulley, same tension?

Hi, I am new here! 1. There is no actually data given, I am just supposed to explain why a string that crosses a pulley have the same tension both sides. The pulleys moment of inertia is zero and friction is negligible. There is a little hint in this problem that says; study equation 9-15...