0/0 = 1?

Division by 0 is not defined. It's tempting to say that since every other number divided by itself is 1, so should 0. But this would have some strange consequences. Consider the function
[tex]y=\frac{x}{x}[/tex]
If x is not 0, then y=1. So it seems natural that y should also be 1 at x=0. But now consider this function:
[tex]y=\frac{x}{x^3}[/tex]
When x=0, we also get y=0/0. But when x gets close to 0, y gets larger and larger and approaches infinity. It doesn't seem reasonable to say y=1 when x is zero. This is one reason division by 0 is left behind. Functions that approch 0/0 are important in the study of calculus.

 

In fact, given any real number r, we can find fractions f(x)/g(x) where both f and g have limit 0 (as x goes to a) but f(x)/g(x) goes to r.

By the way, while we say that a/0, for a not 0, is "undefined", it is common to say that 0/0 is "undetermined". If we try to set a/0= x then we must have a= 0(x) which is impossible. On the other hand, if 0/0= x then we must have 0= 0(x) for which is true for all values of x.

 

Remember that EVERY fraction a/b can be seen as the product a*(1/b)

The number (1/b) is that number which multiplied with b yields 1, i.e, b*(1/b)=1, by definition of 1/b.
1/b is called the reciprocal of b.

However, without resorting to any idea of reciprocals at all, we may prove that for ANY number a, we have 0*a=0.
But that means that THERE CANNOT EXIST A NUMBER 1/0!!!

Therefore, the reciprocal 1/b can only be defined for numbers not equal to zero.

Thus, the expression 0/0=0*1/0 tries to do the impossible thing, namely multiplying together something that IS a number (0), and something that ISN't a number (1/0). But multiplication requires that both factors are, indeed, numbers..

 

I never understood a thing... isn't right to say that:

[tex]\frac{0}{0}=\mathbb{R}[/tex]

When i can't solve a problem, can i go to the prof saying:" the solution is 0/0!!!!"?

 

R is a set. Are you asserting that, what ever 0/0 is, it is a set?

 

yes. for example, the limits in the indeterminate form, if it can be removed, they can assume any result in R you wish. or not?

 

In this case, you have devised a fantasy function having two real arguments going to some set of sets. Nothing wrong with that of course, except it hasn't anything to do with a BINARY OPERATION, like multiplication or division.

 

Sure you could choose to have a function where you choose whatever value from the real numbers you want, but you will find picking the right number is pretty hard :P

 

There's a problem in your second step =).

It'd be (0*3)/(0*3). Even then, it'd be 0 in the end.

But it's just fantasy math with a lot of problems/flaws in the reasoning heh.

 

It doesn't matter if they are equivalent, since it is obviously the case that 0*3=0.

 

Then you have the case of saying 0/0 = 1; when before you stated 0 = 0*3... Where in you have 0/0 = 3 :p. A lot of flaws.

You can't switch things up like that just because you feel like it.

 

Obviously there are flaws. Was that unexpected? Division by zero is not defined. 0=0*3 is a common fact that follows from axioms for the real numbers, nowhere did we say 0/0=3, but this "disproof" is based on an assumption that 0/0=1.

If they are EQUAL you certainly can. You seem to be saying something along the lines of I can't interchange 2² and 4. despite the fact that they are the same thing.

 

The thread has seem to run its course, so I'm closing it.