# 0=1 or is it my mistake?

1. Jun 7, 2010

### 3.1415926535

Obviously it is my mistake but i am wondering what is the mistake i made. First of all, i didn't know how to type math in this forum so i attached a word document with my "idea"

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2. Jun 7, 2010

### arildno

Your mistake lies in assuming that the constant of integration must be the same "c".
It won't be.

3. Jun 7, 2010

### 3.1415926535

could you explain a little more?

4. Jun 7, 2010

### 3.1415926535

nicksauce , i got an email that you replied but i can't see your post

5. Jun 7, 2010

### elibj123

In an indefinite integration you will get a constant c. It doesn't have to be the same in b oth integrals so the constant in the right integral will cover for the addition of '1'.

In definite integration, you will need to put the boundaries on 1 to.
So it will be lie:

$$1_{x=b}-1_{x=a}$$

Which is of course zero, and therefore there is no contradiction.

6. Jun 7, 2010

### 3.1415926535

elibj123, thank you very much I was referring to indefinite integration and i understand now. Again thanks