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We know that1+1 = 2.

but try this out..there is some dummy things goes around here

Firstly, we denote

1 + 1 = 1 + [tex]\sqrt{1}[/tex]

<=> 1 + [tex]\sqrt{(-1)(-1)}[/tex]

<=> 1 + [tex]\sqrt{-1}[/tex][tex]\sqrt{-1}[/tex]

<=> 1 + i*i

<=> 1 + (-1)

<=> 0 ??

how come 1+1=0 ?

and where is the mistake ?

Is it true 1 = [tex]\sqrt{1}[/tex] ?

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# 1 + 1 = 0 ?

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