I've see this neat proof:(adsbygoogle = window.adsbygoogle || []).push({});

http://www.youtube.com/watch?v=E-d9...eature=iv&annotation_id=annotation_3085392237 (for some reason the youtube tag didn't work in preview...)

And now I don't see how what I've learned about series convergence is true...

I've been told that if [itex]a_n > b_n \forall n[/itex] then [itex] \sum a_n > \sum b_n [/itex] therefore, if [itex] \sum b_n [/itex] is divergent then, [itex] \sum a_n [/itex] must be too.

Also, If the partial sum diverges, the series is said to be divergent, isn't it?

And what about [itex] a_n \neq 0 [/itex] for n that tends to infinity?

So many ways I could show this series diverges, yet he show it's equal to -1/12???

Where am I, or is he, wrong?

**Physics Forums - The Fusion of Science and Community**

# 1+2+3+4+...=-1/12? proof

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: 1+2+3+4+...=-1/12? proof

Loading...

**Physics Forums - The Fusion of Science and Community**