1. The problem statement, all variables and given/known data A layer of oil that has a density of 930kg/m^3 is floating on the surface of water in a container if a wooden cube with a length of 4 cm becomes submerged where it's lower half is in water and it's upper half is in oil the cube's density is 960kg/m^3 find A) the buoyancy force affecting the cube B) the length of the cube that is submerged in water 2. Relevant equations density=m/v buoyancy=density*volume*gravity cubic volume=L^3 3. The attempt at a solution so I know the cube's density is less than water so it floats so I use FB=Fg. 960=m/0.04^3. m=0.06144 FB = 0.06144*9.81=0.6027N is that correct? B)FB=Fg 1000*Vsubmegred*9.81=0.6027 V=0.000061m^3 0.04*0.04*L=V L=0.038 now this is my problem the answer sheet says that the submerged part's length is 1.71*10^-2 I can't seem to find the significance of oil and it's density what am I doing wrong?