# 1 object constant acceleration

1. Feb 4, 2005

### runner1738

A car, moving along a straight stretch of highway,begins to accelerate at .0483 m/s^2. it takes teh car 35.9 to cover 1 km. how fast was teh car going when it first began to accelerate? answer in m/s

2. Feb 4, 2005

### MathStudent

35.9 ?? seconds?? minutes??

what are your ideas so far...

3. Feb 4, 2005

### christinono

Look at the list of kinematics formulae you have (if you have any) and decide which one will allow you to find the initial velocity while using the info you were given.

4. Feb 4, 2005

### runner1738

it was 35.9 s sorry

5. Feb 4, 2005

### christinono

Hint hint:
$$d=V_it + \frac{1}{2}at^2$$

6. Feb 5, 2005

### runner1738

1000=1.73397+644.405a, a=1.549128312, wasnt right anymore ideas?

7. Feb 6, 2005

### xanthym

{Distance} = {Initial Velocity}*{Time} + (1/2)*{Acceleration}*{(Time)^2}
(1000) = {Initial Velocity}*(35.9) + (1/2)*(0.0483)*{(35.9)^2}
(1000) = {Initial Velocity}*(35.9) + 31.125
{Initial Velocity} = (968.875)/(35.9)
{Initial Velocity} = (26.988 m/sec) = (60.37 mph)

Last edited: Feb 6, 2005