- #1

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I've broken it down to a problem like this: Let x=99! Then 100! = 100*99! = 100x. 100x - x=99x = 99*99!.

I can't figure out a way to simplify the problem any more than that.

Thank you in advance for any help.

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- Thread starter srfriggen
- Start date

- #1

- 301

- 4

I've broken it down to a problem like this: Let x=99! Then 100! = 100*99! = 100x. 100x - x=99x = 99*99!.

I can't figure out a way to simplify the problem any more than that.

Thank you in advance for any help.

- #2

HallsofIvy

Science Advisor

Homework Helper

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There is the obvious: 100!- 99!= 99!(100- 1)= 99!(99).

- #3

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- #5

Borek

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http://www.wolframalpha.com/input/?i=99*99!&dataset=

Edit: lol, too much time spent to attach the image.

Edit: lol, too much time spent to attach the image.

- #6

arildno

Science Advisor

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Gold Member

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As is seen, "!" does not satisfy the distributive law for operations.

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