Quantum Tunneling and Heat Distribution in Laser Cavities?

In summary, the reflectivity of a mirror in a laser cavity cannot be 100%, as there will always be some losses. If the reflectivity is increased, the laser will stop outputting light and generate more heat instead. This will not destroy the mirrors, but the laser medium will become more excited and additional heat will be produced. The wavelength of a laser is determined by the atomic or molecular transitions that are amplified, and while temperature can affect the relative intensity of different transitions, it has a small effect on the wavelength. This is relevant for LEDs and laser diodes, but for other types of lasers, the effect is negligible.
  • #1
Daniel Petka
122
12
What if I replaced the half transparent mirror in a laser cavity with a 100% reflective mirror?
-would all photons escape due to the quantum tunneling effect?
-would the mirrors melt?
Thanks :biggrin:
 
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  • #2
There are no 100% reflective mirrors. Every component of the laser has some losses. The intensity would increase until the losses match the gain.
 
  • #3
Ty
 
  • #4
Usually, lasers are not very efficient at converting input power to laser light. Most of it gets converted to heat, which needs to be dissipated somehow. If you made the reflectivity very high, then the laser would just stop outputting light, and instead would generate a little more heat. It probably wouldn't destroy the mirrors, since the laser wasn't very efficient to begin with, and increasing the heat a little probably won't overtax the heat sinks.

In a laser, you have a laser medium with multiple excited states. For simplicity, let's consider a three state system. G is the ground state. A is the upper state, and B is the middle state. The power supply is connected to some arc source which excites the laser medium to the A and B states. A decays to B faster than B decays to G, so you get a population inversion between B and the G. So, you get lasing for the B to G transition. But the A to B transition photons are basically lost somewhere, and I guess they get converted to heat eventually. If you turn up the reflectivity, you'll reach some steady state field energy in the cavity, and all the extra power gets converted to heat. Since there is no laser power being carried away, the laser medium becomes more excited and you have more A to B transitions creating heat.
 
  • #5
So cooling the laser should make the wavelength shorter, right?
 
  • #6
Nope. The wavelength is determined by what atomic or molecular transitions are amplified.
 
  • #7
Khashishi said:
Nope. The wavelength is determined by what atomic or molecular transitions are amplified.

Well then I suppose you should see some leds or lasers in liquid nitrogen
 
  • #8
LEDs are not lasers.

The transition energies depend weakly on the temperature, the relative intensity of different transitions (if applicable) depends more on the temperature. That is relevant for LEDs and still notable for laser diodes, for other types of lasers it is a tiny effect. Here is an estimate of 0.3 nm/K for laser diodes.
 

What is a 100% reflective laser cavity?

A 100% reflective laser cavity is a type of optical cavity used in lasers, where all of the light that enters the cavity is reflected back and forth between the mirrors. This creates a highly concentrated and amplified beam of light.

How does a 100% reflective laser cavity work?

A 100% reflective laser cavity works by using two mirrors placed at opposite ends of the cavity. One mirror is fully reflective, while the other is partially reflective. The fully reflective mirror reflects all of the light back into the cavity, while the partially reflective mirror allows a small amount of light to escape as the laser beam.

What are the advantages of a 100% reflective laser cavity?

One of the main advantages of a 100% reflective laser cavity is its ability to produce a highly concentrated and powerful beam of light. It also allows for precise control over the laser's output and can be used in a variety of applications such as cutting, welding, and medical procedures.

What materials are used to make a 100% reflective laser cavity?

The mirrors in a 100% reflective laser cavity are typically made of high-quality optical materials such as glass, fused silica, or metal-coated mirrors. These materials have high reflectivity and can withstand the high intensity of the laser beam without getting damaged.

Are there any limitations to using a 100% reflective laser cavity?

While a 100% reflective laser cavity has many advantages, it also has some limitations. These include the potential for thermal damage to the mirrors due to the high intensity of the laser beam, and the need for precise alignment of the mirrors to maintain the cavity's functionality.

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