# 100th derivative

1. Oct 28, 2007

### rteng

how would be the best way to do this?

I mean, I know how to find the derivative...

and it kind of makes a pattern...but I can't quite correlate that pattern to the 100th derivative

2. Oct 28, 2007

### rock.freak667

Find f'(x).then f''(x) and then f'''(x) and see if you find a pattern happening so that you can find the nth derivative of f(x)

3. Oct 28, 2007

### rteng

dammit

ha k thanks

4. Oct 28, 2007

### ZioX

$$y^{(n)}(x) = \sum_{k=0}^n {n \choose k} u^{(n-k)}(x)\; v^{(k)}(x)$$

This is known as the Leibniz rule (where y(x)=u(x)v(x)).