Coulomb's Law: Find Force of 4.0 & 6.0 $\mu C$ Charges

In summary, the problem involves two charges, $q_1=4.0 \mu \, C$ at the origin and $q_2=6.0 \mu \, C$ at $x=3.0 m$ on the x-axis. We are asked to find the force on $q_2$ and $q_1$, and also how the answers would differ if $q_2$ was $-6.0 \mu \, C$. Using Coulomb's law, $F=\dfrac{k q_1 q_2}{r^2}$ or $F=\dfrac{1}{4 \pi \epsilon _0} \dfrac{q_1 q_
  • #1
karush
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$\tiny{18.3.6 Coulomb's Law }$
$\text{A charge of $q_1=4.0 \mu \, C$ is at origin, and charge}$
$\text{$q_2=6.0 \mu \, C$ is on the x-axis at $x=3.0 m$ }$,
$\text{(a) find the force on the charge $q_2$ } $
$\text{(b) find the force on $q_1$ } $
$\text{(c) how would your answer for parts (a) and (b) dffer if $q_2=-6.0 \mu \, C $ }$

ok I plan to take physics 151this fall
so trying to do some expected problems early
 
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  • #2
karush said:
$\tiny{18.3.6 Coulomb's Law }$
$\text{A charge of $q_1=4.0 \mu \, C$ is at origin, and charge}$
$\text{$q_2=6.0 \mu \, C$ is on the x-axis at $x=3.0 m$ }$,
$\text{(a) find the force on the charge $q_2$ } $
$\text{(b) find the force on $q_1$ } $
$\text{(c) how would your answer for parts (a) and (b) dffer if $q_2=-6.0 \mu \, C $ }$

ok I plan to take physics 151this fall
so trying to do some expected problems early
Start with Coulomb's law!

\(\displaystyle F = \dfrac{k q_1 q_2}{r^2}\) or \(\displaystyle F = \dfrac{1}{4 \pi \epsilon _0} \dfrac{q_1 q_2}{r^2}\)

(Hint: The force on q1 is the same as the force on q2. Why?)

-Dan
 

1. What is Coulomb's Law?

Coulomb's Law is a fundamental law of electrostatics that describes the force between two charged particles. It states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

2. How do you find the force between two charged particles using Coulomb's Law?

To find the force between two charged particles, you need to know the magnitude of their charges and the distance between them. You can then use the formula F = k(q1q2)/r^2, where k is the Coulomb's constant, q1 and q2 are the charges of the particles, and r is the distance between them.

3. What is the unit of force in Coulomb's Law?

The unit of force in Coulomb's Law is Newtons (N). This is because force is a derived unit, and the SI unit for charge is Coulombs (C), distance is meters (m), and the Coulomb's constant has the unit Nm^2/C^2.

4. Can Coulomb's Law be used to find the force between more than two charged particles?

Yes, Coulomb's Law can be used to find the force between any number of charged particles. The force between each pair of particles can be calculated separately using the formula F = k(q1q2)/r^2, and then the total force can be found by vector addition of all the individual forces.

5. What is the significance of the sign (+/-) in Coulomb's Law?

The sign in Coulomb's Law indicates the direction of the force between two charged particles. A positive sign indicates that the force is repulsive, meaning the particles will push away from each other. A negative sign indicates an attractive force, meaning the particles will be pulled towards each other.

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