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1998 Physics B

  1. Feb 15, 2012 #1
    1. The problem statement, all variables and given/known data

    Problem is part 6 (c) on page 9 of pdf file.


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    Code (Text):

    2. Relevant equations

    λ8= 2L/8

    f8= 8f1

    V = √(F/(m/L))

    3. The attempt at a solution

    Okay, I found that the speed of transverse waves is 288m/s
    which gives me a tension force of 8.2944N on the string.

    λ4= (2L)/4
    λ4 = 0.6m

    (4 x 120hz)(0.6m) = 288 m/s

    I don't know how to set up the equations to find the speed of the transverse waves on the string when the number of loops is equal to 8.

    I keep getting the same velocity..

    λ8= 0.3m
    f8= 960hz

    V= f8 x λ8 = 288 m/s ?
    Last edited: Feb 15, 2012
  2. jcsd
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