- #1
JinM
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Homework Statement
[itex]\frac{dy}{dx} = \frac{3x+2y}{3x+2y+2}[/itex]
2. The attempt at a solution
I thought I'd let u = 3x+2y+2, which would give me this,
[itex]u' = 5 - \frac{4}{u}[/itex]. This is seperable, and we thus get
[itex]\frac{1}{5}(3x + 2y +2) - \frac{4}{25}\ln|5(3x+2y+2)-4| = x + C[/itex]
Can someone check this? I've been differentiating this beast and I keep getting different coefficients. Is what I got here correct?
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