- #1

Eduard1

- 7

- 0

Let's consider a Copper bulk material. This one can be reproduce (ad infinitum) by using a cubic unit cell (fcc) of lattice constant

**a**. Let's cut this bulk along the (110) plane and expose the Cu(110) surface to the vacuum. My question is: which are the x and y dimensions of a (1x1) unit cell ? After my calculations the 1x1 unit cell, on the Cu(110) surface, will have the x and y dimensions of

**a**and

**a*sqrt(2)**. However, according to my solid state course, the x and y dimensions of a 1x1 unit cell, on the Cu(110) surface, are of

**a**and

**a*sqrt(2)/2**. I simply can not understand from where it is coming the division to 2. I would expect to have only

**a*sqrt(2)**as this is a cube face diagonal (and we cut along a cube face diagonal to get the 110 surface).

Can anyone help me with an explanation?

With all the best wishes,

Eduard