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Mathematics
General Math
-2.4.27 find center and radius of circle
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[QUOTE="karush, post: 6786035, member: 703413"] Determine the graph of $x^2+y^2+6x+8y+9=0$ $\begin{array}{rll} \textsf{rewrite} &(x^2+6x )+(y^2+8y)=-9\\ \textsf{complete square} &(x^2+6x+9)+(y^2+8y+16)=-9+9+16\\ \textsf{simplify equation} &(x+3)^2+(y+4)^2=16=4^2\\ \textsf{observation} &C(-3,-4), \quad R=4 \end{array}$ hopefully ok is there another way to do this other than complete the square if you are inclined to do so I would be interested in a tikz code would be fore this :unsure: [/QUOTE]
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Forums
Mathematics
General Math
-2.4.27 find center and radius of circle
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