1. The problem statement, all variables and given/known data I think I have a solution to this but I might have made a logical error so I want to check if my reasoning works. You have two capacitors one charged by some unspecified mean to a paricular voltage. It is connected then connected to another capacitor in parallel with resistor somewhere in the loop. What is the heat dissipated through the resistor? 2. Relevant equations v = v0 * e^(-t/RC) discharging capacitor P = V^2/ R heat dissipation through resistor C = Q/V 3. The attempt at a solution Charge is conserved in the situation so regardless of the capacitor eventually the potential difference of the 2 capacitors is the same Q = C1V1 VFinal = Q/(C1+C2) We can find the time it took for the orginal capacitor to discharge the amount need to reduce the potential difference to Vfinal namely t = -RC * ln(vf/v0) then we can look at the infinetessimal amount of heat disappainted at each time dW = V(t)^2/R dt then you take the integral from 0 to t as shown and get some number. I see a potential problem with this though. Since the given potential at time t is that of the capacitor do I instead of to use the current through the resistor at time t and then integrate over dW = I(t)^2/R dt? Also I feel like I'm discounting whatever changes to the current/ potential to the wire will happen as a result of capacitor 2 charging. I feel that since I know the amount of charge that moved through the resistor I should just easily be able to calculate the energy loss. What principle am I missing?