# 2 capacitors connencted

## Homework Statement

a capacitor C1 2.4uF charged to a voltage of 880V and a second capacitor C2 4.0uF charged to 560V. They are disconnected from their batteries and their positive plated and connected together, and their negative plated are connected together. What will the final voltage and charge on each be after a long time? They are then connected negative to positive..and same question as before.

Q=CV

## The Attempt at a Solution

I don't really have a clue. However, I found the charge on each capacitor initially then added them together, and found the percent for each capacitor (C1/(C1+C2)) and times it by the total charge. Does that even make sense? because the answer was right. Are you able to add the capacitors in any way? are they in series or parallel? the voltages of them were the same as if they were in parallel. AH!

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Astronuc
Staff Emeritus
Find the charge Q1 on C1 and Q2 on C2.

The total charge has to be conserved.

Then find the combined capacitance in parallel, and find the voltage based on the total charge and effective capacitance.

Find the charge Q1 on C1 and Q2 on C2.

The total charge has to be conserved.

Then find the combined capacitance in parallel, and find the voltage based on the total charge and effective capacitance.
This works for the first case where the 2 positive ends are connected. In the second case where the positive is connected to the negative of the other it doesn't..whether you add the capacitances in parallel or series?! The voltage and charge on each is much smaller.