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Homework Help: 2-d collisions

  1. Nov 1, 2009 #1
    1. The problem statement, all variables and given/known data

    Two coins, one at rest (c1), the other flicked towards the other (c2). Initial positions are marked, as are final positions and angles. Coordinate system's origin is placed at center of C1 with +x in direction of C2's motion.
    [tex]\mu[/tex] = .36
    V1 = 0
    C1 final position- 10.25 cm @ 16 degrees
    C2 final position- 5.6 cm @ 302 degrees (-58 degrees)
    m1 = m2


    2. Relevant equations

    m2v2 = m1fv1fcos(16) + m2fv2fcos(302)

    0 = m1fv1fsin(16) + m2fv2fsin(302)

    (cons. of KE)

    1/2m1v12 + 1/2m2v22 = 1/2m1fv1f2 + m2fv2f2

    (acceleration? idk if this is necessary...)

    a = [tex]\mu[/tex]g
    -- derived from [tex]\Sigma[/tex]F = ma = [tex]\mu[/tex]mg... not sure if there should be any other forces in this...

    3. The attempt at a solution

    i keep getting .36587vf2 = 2.0767vf2

    i have a feeling i need to find v2 right before collision using v2 = vo2 + 2a(x-xo)
  2. jcsd
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