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Here is my following question

**1. During volcanic eruptions, chunks of solid rock can be blasted out of the volcano; these projectiles are called volcanic bombs. Figure 4-58 shows a cross section of Mt. Fuji, in Japan. (a) At what initial speed would a bomb have to be ejected, at angle θ0 = 35˚ to the horizontal, from the vent at A in order to fall at the foot of the volcano at B, at vertical distance h = 2.90 km and horizontal distance d = 9.00 km? Ignore, for the moment, the effects of air on the bomb's travel. (b) What would be the time of flight?**

**2. y = (tan theta)x - (gx^2) / 2(V0costheta0)^2**

**3. The above equation listed is the only thing that I can think of that works, usually constant acceleration equations aren't seem to getting anywhere for me. But anyways, I solved the equation to just the initial velocity (V0), just wanted you guys' opinions on whether this is the right approach to the problem**

Thanks,