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## Homework Statement

A ball is thrown straight upward and returns to the thrower’s hand after 1.54 s in the air. A second ball is thrown at an angle of 30.0◦ with the horizontal.

The acceleration of gravity is 9.81 m/s2 .

At what speed must the second ball be thrown so that it reaches the same height as the one thrown vertically?

Answer in units of m/s.

## Homework Equations

DeltaX=Vi(DeltaT)+1/2gDeltaT^2

Any others unknown

## The Attempt at a Solution

I've tried approaching the problem, but I can't seem to get started, first off, I'm unaware of how I would get the height of the first ball.

After I would get the height of the first ball, I know what I would do.