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2-D Motion

  • Thread starter Leeee
  • Start date
  • #1
5
0

Homework Statement


A ball is thrown straight upward and returns to the thrower’s hand after 1.54 s in the air. A second ball is thrown at an angle of 30.0◦ with the horizontal.
The acceleration of gravity is 9.81 m/s2 .
At what speed must the second ball be thrown so that it reaches the same height as the one thrown vertically?
Answer in units of m/s.


Homework Equations


DeltaX=Vi(DeltaT)+1/2gDeltaT^2
Any others unknown


The Attempt at a Solution


I've tried approaching the problem, but I can't seem to get started, first off, I'm unaware of how I would get the height of the first ball.
After I would get the height of the first ball, I know what I would do.
 

Answers and Replies

  • #2
5
0
Solved. Nevermind.
 

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