A ball is thrown straight upward and returns to the thrower’s hand after 1.54 s in the air. A second ball is thrown at an angle of 30.0◦ with the horizontal.
The acceleration of gravity is 9.81 m/s2 .
At what speed must the second ball be thrown so that it reaches the same height as the one thrown vertically?
Answer in units of m/s.
Any others unknown
The Attempt at a Solution
I've tried approaching the problem, but I can't seem to get started, first off, I'm unaware of how I would get the height of the first ball.
After I would get the height of the first ball, I know what I would do.