1. The problem statement, all variables and given/known data Darryl drives his load of tomatoes 14.0 km [E], 6.0 km [N], 12.0 km [ N 15° E], and then 2.0 km [N 65° E]. This takes him 42 minutes. Calculate Darryl's distance and displacement. a) Calculate Darryl's distance and displacement. Draw a diagram and show your work. b) Calculate Darryl's average speed and average velocity (record your answer in m/s). 2. Relevant equations tan∅=opposite/adjacent C^2 = a^2 + b^2 c(squared)=a(squared) +b(squared)=2abcos∅ 3. The attempt at a solution so i've tried drawing this and it seems that i have 2 triangles. so i tried to solve for Δd on the first triangle using the cosine law. to get the angle i used Tan tan∅=6km/14km=23° c(squared)=a(squared) +b(squared)=2abcos∅ = 6(squared)+14(squared)-2(6)(14)cos23° =8.7km [second triangle] tan∅=2km/12km = 9.4° c(squared)=a(squared) +b(squared)=2abcos∅ =2(squared)+12(squared)-2(12)(2)cos9° =100.5km so then i figured add them together and my Δd = 109.2 km now honestly this just doesn't seem right to me at all I'm not sure how i should be approaching this but i'm getting really flustered cause i'm completely stumped by vectors right now and it's starting to turn me away from physics.