# 2 different dy/dx of xy=c^2

## Main Question or Discussion Point

I have a relation xy=c2 , if i apply implicit differentiation to both sides i get dy/dx =-y/x , but if i write the same thing as y=c2/x , then dy/dx comes out to be -c2/x2 , whats going wrong ??????

Office_Shredder
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I have a relation xy=c2 , if i apply implicit differentiation to both sides i get dy/dx =-y/x , but if i write the same thing as y=c2/x , then dy/dx comes out to be -c2/x2 , whats going wrong ??????
If xy=c2, then y=c2/x. So -y/x = -c2/x2 You got the same answer, just in a different form

quasar987