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2 different dy/dx of xy=c^2

  1. Oct 1, 2009 #1
    I have a relation xy=c2 , if i apply implicit differentiation to both sides i get dy/dx =-y/x , but if i write the same thing as y=c2/x , then dy/dx comes out to be -c2/x2 , whats going wrong ??????
     
  2. jcsd
  3. Oct 1, 2009 #2

    Office_Shredder

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    If xy=c2, then y=c2/x. So -y/x = -c2/x2 You got the same answer, just in a different form
     
  4. Oct 1, 2009 #3

    quasar987

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    Nothing since -y/x = -c²/x2 !
     
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