2 different dy/dx of xy=c^2

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I have a relation xy=c2 , if i apply implicit differentiation to both sides i get dy/dx =-y/x , but if i write the same thing as y=c2/x , then dy/dx comes out to be -c2/x2 , whats going wrong ??????
 

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  • #2
Office_Shredder
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I have a relation xy=c2 , if i apply implicit differentiation to both sides i get dy/dx =-y/x , but if i write the same thing as y=c2/x , then dy/dx comes out to be -c2/x2 , whats going wrong ??????
If xy=c2, then y=c2/x. So -y/x = -c2/x2 You got the same answer, just in a different form
 
  • #3
quasar987
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I have a relation xy=c2 , if i apply implicit differentiation to both sides i get dy/dx =-y/x , but if i write the same thing as y=c2/x , then dy/dx comes out to be -c2/x2 , whats going wrong ??????

Nothing since -y/x = -c²/x2 !
 

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