Xy=Voyt + 1/2at^2
The Attempt at a Solution
I calculated the vertical and horizontal velocity components of the given resultant velocity of 240 m/s.
Voy = 120 m/s
Vox = 208 m/s
then i used the vertical component, the given vertical distance and gravity to calculate the time needed for the package to fall to the ground.
t = 38 s
then i plugged this into Xx=1/2(Vox+Vx)t to find the horizontal distance the package travelled.
then i plugged this in with the given vertical distance into tan -1 (y/x) to get an angle of 31 degrees. but the book says 42 degrees! where did i go wrong guys?
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