(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

http://img413.imageshack.us/img413/2919/physicsprobpr6.jpg [Broken]

Xy=2400 m

2. Relevant equations

Xy=Voyt + 1/2at^2

Xx=1/2(Vox+Vx)t

3. The attempt at a solution

I calculated the vertical and horizontal velocity components of the given resultant velocity of 240 m/s.

Voy = 120 m/s

Vox = 208 m/s

then i used the vertical component, the given vertical distance and gravity to calculate the time needed for the package to fall to the ground.

t = 38 s

then i plugged this into Xx=1/2(Vox+Vx)t to find the horizontal distance the package travelled.

Xx= 3904

then i plugged this in with the given vertical distance into tan -1 (y/x) to get an angle of 31 degrees. but the book says 42 degrees! where did i go wrong guys?

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# 2 dimen kinematics problem

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