1. The problem statement, all variables and given/known data Xy=2400 m 2. Relevant equations Xy=Voyt + 1/2at^2 Xx=1/2(Vox+Vx)t 3. The attempt at a solution I calculated the vertical and horizontal velocity components of the given resultant velocity of 240 m/s. Voy = 120 m/s Vox = 208 m/s then i used the vertical component, the given vertical distance and gravity to calculate the time needed for the package to fall to the ground. t = 38 s then i plugged this into Xx=1/2(Vox+Vx)t to find the horizontal distance the package travelled. Xx= 3904 then i plugged this in with the given vertical distance into tan -1 (y/x) to get an angle of 31 degrees. but the book says 42 degrees! where did i go wrong guys?