1. The problem statement, all variables and given/known data The stretchy silk of a certain species of spider has a force constant of 1.50 . The spider, whose mass is 15mg, has attached herself to a branch as shown in the figure. Figure: http://session.masteringphysics.com/problemAsset/1348379/2/5-70.jpg a)Calculate the tension in each of the three strands of silk. b) Calculate the distance each strand is stretched beyond its normal length. 2. Relevant equations Worked with the equations: Tc=Tacos(30) + Tbcos(40) for vertical components where Tc=mg=147 mN. And for the horizontal Tasin(30) = Tbsin(40). Found the ratio and plugged back into the equations to find Tb and then Ta. 3. The attempt at a solution Using the relevant equations, I derived Ta = Tb x 1.286 and ultimately got answers: Ta=100mN, Tb=78.2mN, and Tc=147mN.