1. The problem statement, all variables and given/known data A plane with an initial velocity of (225m/s ŷ + 325m/s Ẑ) intercepts a 20kg piece of luggage with initial velocity of (-75m/s ŷ - 15m/s Ẑ). After, plane is moving at speed 400 m/s. What is the mass of the plane? 2. Relevant equations momentum y: Mplane(225m/s) + 20kg(-75 m/s) = Mplane(Vy) + 20kg(Vy) momentum z: Mplane(325m/s) + 20kg(-15m/s) = Mplane(Vz) +20kg(Vz) V = Vy^2 + Vz^2 , Tanθ= Vz/Vy 3. The attempt at a solution I know the speed given after the interception is in magnitude form and it needs to be in component form and the speed of the plane and luggage are the same after. For the plane I get V=395.3m/s @ 55.3° For the luggage I get V=76.5m/s @ 11.3° (assuming this means the Luggage starts in Q1 and moves on the 11.3° angle into Q3?) I tried doing conservation of momentum with plugging in 400 in the final velocities but I realized this does not make sense.