Two basic limit problems just solve the limit if it exists. I know the answers but I don't understand why the answers are what they are.(adsbygoogle = window.adsbygoogle || []).push({});

1.) lim (x^2-x-2) / (x-2)^2

x->2

2.) lim ((1/x)-(1/2)) / (x-2)

x->2

Answers were:

1.) DNE

2.) -1/4

I kind of understand that the first problem the denominator would be 0, but I thought if you factored the top and bottom you could find the limit of (x+1).

The second one I am completely stuck the only thing I could think to do was use the division rule but I would still have 0 for the denominator. If anyone could explain this it would be a big help.

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# 2 lmit problems

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