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Homework Help
Introductory Physics Homework Help
Solve 2-Mass Pulley System Homework for Moving Blocks
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[QUOTE="dgZeyas, post: 4507651, member: 488315"] [h2]Homework Statement [/h2] A massless string, passing over the frictionless pulley, connects the two masses as shown. Block m[SUB]1[/SUB] hangs vertically without touching the wall, but m[SUB]2[/SUB] slides along the wall with friction (μ[SUB]s[/SUB] = 0.61, and μ[SUB]k[/SUB] = 0.14). If θ = 53°, how many times heavier than block 1 must block 2 be to start the system moving? [ATTACH=full]164083[/ATTACH] [h2]Homework Equations[/h2] 1. ƩF[SUB]x[/SUB] = ma[SUB]x[/SUB] and ƩF[SUB]y[/SUB] = ma[SUB]y[/SUB] 2. [I]f[/I][SUB]s[/SUB] = μ[SUB]s[/SUB]N 3. [I]f[/I][SUB]k[/SUB] = μ[SUB]k[/SUB]N [h2]The Attempt at a Solution[/h2] I set up a free body diagram for m[SUB]2[/SUB], oriented as it is in space, such that the positive x-direction points up the slope and the positive y-direction points perpendicularly out of the slope. Then the forces are as follows: T (tension): + x-direction W (weight): m[SUB]2[/SUB]gsinθ in the -x-direction and m[SUB]2[/SUB]gcosθ in the -y-direction N (normal): +y direction [I]f[/I][SUB]s[/SUB] (static friction): +x-direction (when m[SUB]2[/SUB] is NOT moving) [I]f[/I][SUB]k[/SUB] (static friction): -x-direction (when m[SUB]2[/SUB] IS moving) So I figured the static friction would be this: [I]f[/I][SUB]s[/SUB]= μ[SUB]s[/SUB](m[SUB]2[/SUB])(g)(sinθ) as per equation 2. But this is about as far as I got. I'm trying to find how many times heavier than block 1 must block 2 be to start the system moving-- I inferred from this that block 2 would move UP the ramp if block 1 was heavier, which makes sense, and while I have an equation containing m[SUB]2[/SUB], I'm having trouble figuring out another equation so a ratio can be set up. Any help appreciated, thanks in advance! [/QUOTE]
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Solve 2-Mass Pulley System Homework for Moving Blocks
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