2 masses and 1 spring jumping object question

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In summary, we have discussed the equations and constraints involved in determining the maximum height reached by the robot's centroid, the vertical accelerations of the two masses, and the instantaneous heights of the masses in relation to the length of the spring.
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alldan25889
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Here is a question as part of my coursework.
A spring of stiffness k connects a part of a jumping robot that rests on the ground of mass M1 to a free mass M2. When fully compressed the spring has length Lc and relaxed has length Lr. Sping has negligible mass and can be streched and compressed...
Questions:
a) Assuming 100% efficiency, to what height will the robot's centroid jump above where it started?
b) Derive two equations that describe vertical acceleratiosn of the two masses and derive a third that relates their instantaneous heights by the length of the spring
c) If solving these equations, what additional conraints would have to be applied to the instantaneous height of M1?

I have had a go at the first question and equated the (m1+m2)gh = 1/2 k (Lr-Lc)^2. I know that the value for h is not exactly what would be the height. For question 2 I attempted isolated free body diagrams for both masses and obtained the following expressions. m2 x a2 = k x (extension) and m1 = -m1g + k (extension). Where extension = height traveled by m2 - height traveled by m1.

Would appreciate your opinions.
Allen
 
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For question a), the answer to your equation is the maximum height that the centroid of the robot will reach, assuming perfect efficiency. For question b), you are correct that you need two equations to describe the vertical accelerations of the two masses, and a third equation that relates their instantaneous heights by the length of the spring. The two equations for the accelerations should be:m1*a1 = -m1*g + k*(Lr-Lc) m2*a2 = k*(Lr-Lc) The third equation relating the instantaneous heights is derived from the conservation of energy, which states:m1*gh1 + m2*gh2 = 1/2*k*(Lr-Lc)^2 This equation can be rearranged to solve for the difference in heights of the two masses as a function of the length of the spring:h2 - h1 = (Lr-Lc)^2 / 2g For question c), the additional constraint that would need to be applied to the instantaneous height of M1 is that it must remain at or above the initial height. This means that the value of h1 should never be negative, since it is the difference in heights of the two masses that is being calculated.
 

1. What is the equation for the motion of a system with 2 masses and 1 spring?

The equation for the motion of a system with 2 masses and 1 spring is given by m1a1 = -kx1 + k(x2-x1), where m1 is the mass of the first object, a1 is its acceleration, k is the spring constant, x1 is the displacement of the first object, and x2 is the displacement of the second object.

2. How do the masses and spring constant affect the motion of the system?

The masses and spring constant have a direct impact on the frequency and amplitude of the motion of the system. Increasing the masses will decrease the frequency and increase the amplitude, while increasing the spring constant will increase the frequency and decrease the amplitude.

3. What is the relationship between the displacement of the objects and the spring force?

The displacement of the objects is directly proportional to the spring force. This means that as the objects move further away from their equilibrium position, the spring force will also increase, and vice versa.

4. Is there a maximum displacement for the objects in this system?

Yes, there is a maximum displacement for the objects in this system. This is known as the amplitude and is determined by the initial conditions of the system, such as the initial displacement and velocity of the objects.

5. How does the motion of this system compare to a simple harmonic oscillator?

The motion of this system is similar to a simple harmonic oscillator, as it follows a periodic motion and has a restoring force that is proportional to the displacement. However, the presence of multiple masses and a single spring can result in more complex motion and different frequencies compared to a simple harmonic oscillator.

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