Mass m1=28.1 kg is on a horizontal surface, connected to mass m2= 6.70 kg by a light string as shown. The pulley has negligible mass and no friction. A force of 231.3 N acts on m1 at an angle of 29.5o.
I can't seem to get the correct answer for this one.
I get this equation for the horizontal forces on m1:
m1a = Fcos(theta) -T -ukm1g +ukFsin(theta)
And this one for the vertical forces on m2:
m2a = T -m2g
I can combine these equations and solve for a, but that
doesn't seem to be working out for me. Any suggestions?
The Attempt at a Solution
I plugged in all of the numbers, but it does not seem to be working out