# 2 Mini Q.

1. Jun 20, 2008

### m_s_a

1. The problem statement, all variables and given/known data

http://up5.m5zn.com/photos/00017/t4x1262r70cu.jpg[/URL]
http://up5.m5zn.com/photos/00017/rpbn4bsfcace.jpg[/URL]
2. Relevant equations

3. The attempt at a solution
C1:z(t)=t , 0<t<5
C1:z(t)=5+it , 0<t<5
C2:z(t)=1-t+5i , 0<t<5
C3:z(t)=5-t+5i , 0<t<5
C4:z(t)=i(1-t) , 0<t<5
Is paramitric Equation Correct?

Last edited by a moderator: Apr 23, 2017
2. Jun 20, 2008

### Dick

1) Not really any difference as far as I know. They both indicate integral over the contour C. 2) The parametric form for the contour has several mistakes. Can you find one? I'll get you started. The contour has 4 segments, you've listed 5. Two of them labelled C1. What's up with that?

3. Jun 21, 2008

### m_s_a

Dear
Dick
مرحبا
سعيد يرؤيتك
1)
I can not find an answer in books,In books sometimes use pattern,Sometimes using type IIusing
They both indicate integral over the contour
Do you clarify if possible
2)

C1:z(t)=t , 0=<t=<5
C2:z(t)=5-t+5i , 0=<t=<5
C3:z(t)=5-t+5i , 0=<t=<5
C4:z(t)=i(5-t) , 0=<t=<5
Sorry for error
I will try again.
Thanks
See you

4. Jun 21, 2008

### HallsofIvy

For (1), IF "C" represents the same contour in both integrals, then, as Dick said, they are the same. However, I suspect that the question did not mean to imply that. If the two different "C"s may mean different contours, then the first form implies that C is a closed contour while the second does not.

For (2), now you've got C2 and C3 exactly the same! (Your second "C1" in your first answer should have been "C2".)

5. Jun 21, 2008

### m_s_a

Hi king
O.K.
used (I) for Contour = sum of Curves , and Closed
and used (II) for any Curve

Q.2
Now
z1(t)=t , 0=<t=<5
z2(t)=5+it , 0=<t=<5
z3(t)= t+5i , 5=<t=<0
z4(t)=it , 5=<t=<0

:yuck: