A red car and a green car move toward each other in adjacent lanes and parallel to an x-axis. At time t=0, the red car is at x=0 and the green car is at x=220. if the red car has a constant velocity of 20km/h, the cars pass each other at x=44.5m and if it has a constant velocity of 40km/h, they pass each other at x=76.6m. What are a) the initial velocity of the green car? and b) the acceleration of the green car? so i drew out a picture and said that 20t = 44.5, so t = 2.225s. also i said that 175.5=xt, so x = 78.88m/s. then i used the next set of information and said 40t = 76.6, and found that t = 1.915 and therefore 143.4=xt so x = 74.88m/s. am i supposed to get 2 different velocities? since 74.88 is smaller than 78.88, i said that 74.88 is the initial velocity. for the acceleration, i did 78.88-74.44 / 2.225-1.915 = 12.90m/s^2 is my work correct? my textbook doesn't have the answer for this problem.