# 2 physics Questions

1. Apr 7, 2004

### lotusbloom

2 physics Questions....

1. There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted so that it can be rotated about its axis by turning a hand crank. The outer wall of the cylinder is perforated with small holes. You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 10.2 cm. When the cylinder is rotating at 2.61 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?

2.A car is safely negotiating an unbanked circular turn at a speed of 19.2 m/s. The maximum static frictional force acts on the tires. Suddenly a wet patch in the road reduces the maximum static frictional force by a factor of three. If the car is to continue safely around the curve, to what speed must the driver slow the car?

2. Apr 7, 2004

### Chen

1. Let's get rid of all the excess information (dear God, there is a lot of it!) - we know that the raduis is 0.102 meters and the frequency of the motion is 2.61Hz. Is this enough to find the centripetal acceleration? Let's see. You should know that ac = v2/r. But since v = &omega;r we can say that ac = &omega;2r. We have r, so we just need to find &omega; now... can you do it yourself?

3. Apr 7, 2004

### Chen

2. For the car "to continue safely around the curve", the static frictional force must match the centripetal force that the car should experience as it goes around the curve. So:

$$f_{s_{max}} = F_c$$

Let's expand it a bit:

$$mg\mu _s = ma_c = m\frac{v^2}{r}$$

As the mass cancels we are left with:

$$gr\mu _s = v^2$$

So if $\mu _s$ is reduced by a factor of three, what must be the new speed of the car?

4. Apr 8, 2004

### lotusbloom

so ac = ω2r to find W...is ac = 2.61Hz and r =0.102m put it in to find W then put w in v=wr equation to find V????

5. Apr 8, 2004

### lotusbloom

So the new speed will reduces by three too..is that right????

6. Apr 8, 2004

### Chen

No, it is the frequency, f = 2.61Hz. You still don't know ac, you need to find it. ω is the angular velocity, right? So if the cylinder is rotating at 2.61 revolutions per second, how many radians does it rotate by every second? (Hint: Every circle has 2&pi; radians.)

7. Apr 8, 2004

### Chen

No.

$$gr\mu _s = v^2$$

If $gr\mu _s$ is reduced by a factor of 3, how much is v2 reduced by? How much is v reduced by then?

8. Apr 9, 2004

### lotusbloom

ok i think it got it...so w=5.22, r=10.2cm ( do i need to change that into m)...so then i can find ac right??? then using ac = v^2/r...i can find the velocity right???

9. Apr 9, 2004

### lotusbloom

ok for this one i got an answer of 10.2 m/s....but is wrong...and i don't know why....

10. Apr 9, 2004

### Chen

No, &omega; = 5.22&pi; = 16.4 rad/s. And yes, you need to convert r to meters to get the units of the acceleration correct.

11. Apr 9, 2004

### Chen

How can you get a value for v? The question asked to find how much it would be reduced by if the coefficient of friction was reduced by a factor of 3. If you reduce the value of x2 by a factor of 3, how much is x itself reduced by?