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2 questions please

  1. Apr 5, 2007 #1
    hi, I have 2 questions here that I am stuck on. I thought I may as well stick them in the same topic to avoid cluttering the forum. hope you can help, thnx

    QUESTION 1
    1. The problem statement, all variables and given/known data

    Fred invests an amount of money in an account paying r% compound interest per annum. The amount of money doubles after n years.

    Find a formula for r in terms of n.

    2. Relevant equations



    3. The attempt at a solution

    where m is the initial money]

    [tex]2m = m(\frac{100+r}{100})^{n}[/tex]

    [tex]2 = (\frac{100+r}{100})^{n}[/tex]

    [tex]\sqrt[n]{2} = \frac{100+r}{100}[/tex]

    [tex]100\sqrt[n]{2} = 100 + r[/tex]

    [tex]r = 100\sqrt[n]{2} - 100[/tex]

    now, that seems to be the right answer but looks kinda ugly... first of all, is that answer right? and secondly, if so, is there a nicer way to put it :S ?

    thnx


    QUESTION 2
    1. The problem statement, all variables and given/known data

    Using this result, or otherwise

    I proved for the previous question that

    [tex](m^2+1)(n^2+1) = (m + n)^2 + (mn -1)^2[/tex]


    write 500050 as the sum of 2 square numbers.

    2. Relevant equations



    3. The attempt at a solution

    I havn't been told how to do this. maybe because this is on a past paper it isn't on the syllabus anymore, but still, I'd like to know how to do it because i doubt its that hard once you know how.

    thnx
     
    Last edited: Apr 5, 2007
  2. jcsd
  3. Apr 5, 2007 #2
    correction:

    the latex thing wont let me change it despite me trying a billion times. so basically, in the first use of latex the star thing isnt supposed to be there.

    if mod or whatever can figure out how to remove the star, please do :D thnx
     
  4. Apr 5, 2007 #3

    Dick

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    Your answer to question 1) is correct.

    For 2) write 500050=10001*50 and think about it.
     
    Last edited: Apr 5, 2007
  5. Apr 5, 2007 #4
    done it :D

    107^2 + 699^2

    thnx man

    is there actually an elegant way of picking the factors outa 500050 or is it simply guesstimation?
     
  6. Apr 5, 2007 #5

    Dick

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    I just picked the obvious factors of 500050. If they had chosen odder ones it would have been much harder as I don't know any really systematic way of finding 'square+1' factors except trial and error.
     
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