# 2 questions

1. Nov 29, 2005

Hello,
I have 2 problems that bother me here:
1-
The maximun speed of a mass attached to a spring is v[sub=max[/sub]=.371m/s, while the maximun acceleration is 1.05m/s2.
What is the maximun displacement of the mass?

I tried the equation of v(t)=-A*w*sin(wt+co)
and a(t)=-A*w2*cos(wt+co)
But I get nothing I was thinking to use vmax=a*w...??

2-
When a certain circular uniform motion is projected on the x and y axis,the projection gives:
x(t)=Rsin(w*t+co-pi/2) and y(t)=Rsin(w*t+co).
Show that the circular motion is clockwise.
I have no idea of what to do.
.
Does someone give me some help?
B

2. Nov 29, 2005

### mezarashi

For the first question, I'm going to assume the spring system is horizontal. The maximum velocity happens when the displacement is zero. What does this tell you about the springs total energy? The maximum acceleration occurs when the force acting on the mass is at its max. This occurs when the displacement $$\Delta x$$ is at its max. The two unknowns are the spring constant and the maximum displacement.

3. Nov 30, 2005

### andrevdh

the maximum values occur when the sin and cos terms are one therefore
$$v_{max}=-A\omega$$
and
$$a_{max}=-A{\omega}^2$$
use these to solve for $\omega$
and subsequently for the amplitude.

The second problem can be approached from the standpoint that the tangent of the angle that the rotating vector makes with the x-axis is given by the ratio of the y to the x component.Use the identities
$$\sin(\frac{\pi}{2}-\theta)=\cos(\theta)$$
and
$$\sin(-\theta)=-\sin(\theta)$$
and observe what happens with this angle as time advances.

Last edited: Nov 30, 2005
4. Nov 30, 2005