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2 to 1 Multiplexer

  1. Oct 23, 2013 #1
    Consider f = w1w2! + w1w3 + w1!w2 +w1!w3! Use the truth table to derive a circuit for f that uses a 2-to-1 multiplexer



    I have the truth table, that part is easy. The problem I'm having is what exactly are they EVALUATING to get the f?



    Like I said I have the truth table of 3 input, but I don't know how to evaluate for the f. I know it's like a 0 and a 1. But where do I plug in each etc.
     
    Last edited by a moderator: Oct 23, 2013
  2. jcsd
  3. Oct 25, 2013 #2

    berkeman

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    Staff: Mentor

    Can you please post your work? Show us the truth table, and show what a 2:1 MUX looks like...
     
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