The question asked to solve this initial value problem(adsbygoogle = window.adsbygoogle || []).push({});

(2+x^2)dy/dx = x(y+3)

(2+x^2)dy/(dx*(y+3) = x

dy/[(y+3)*dx]= x/(2+x^2)

dy/(y+3) = x*dx/(2+x^2)

S dy/(y+3) = S x/(2+x^2)*dx

ln(y+3) = ?

Im not sure what to do with the RHS do I do integration by parts?

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# Homework Help: (2+x^2)dy/dx - x(y+3)= 0 , y(0)=-1

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