Object 1 with velocity v hits object 2, of same mass at velocity 2. Prove that the angle between them after the collision is equal to 90 degrees.
PE inital = PE final
KE initial = KE final
The Attempt at a Solution
P x component
m1 x v1 + 0 = (m1)(v'1)(costheta1) + (m1)(v'2)(costheta2)
p y comp
0 = (m1)(v'1)(sintheta1) + (m1)(v'2)(sintheta2)
kinetic E equation simplifies to
v1 - v2 = v'2 - v'1
I can't figure out how to combine the three to a point where they simplify.