- #1

- 78

- 0

I though i know this well but i don't even know how to set this up

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter xstetsonx
- Start date

- #1

- 78

- 0

I though i know this well but i don't even know how to set this up

- #2

- 423

- 2

Try dividing up the problem into two dimensions: the horizontal and the vertical. Questions:

a) What happens as the ball moves upwards (vertical)?

b) What happens as the ball moves forward (horizontal)?

Try answering these and see where they take you.

- #3

- 78

- 0

- #4

- 423

- 2

I'll give you another hint: you don't need to find t. t is going to cancel out at the end, so don't worry about actually finding it yet. We need to set up equations for the horizontal and vertical directions first. These equations will include t as a variable.

The questions in post #2 will help you set up the equations you need, so I want you to try and answer them first.

- #5

- 78

- 0

(200)/(Vicos45)=t=2((Visin4)/(-9.8))

----horizontal----------vertical-----

is that even close?

----horizontal----------vertical-----

is that even close?

- #6

- 423

- 2

Okay, so 200 m / (Vicos45) = t is correct for the horizontal.

And your vertical part is correct too, assuming you meant sin(45), not sin(4).

Now you can solve for Vi.

- #7

- 78

- 0

- #8

- 423

- 2

And the total time (time for it to go up and come back down) is the same time it takes for the ball to travel horizontally 200 m. Does that make sense?

- #9

- 78

- 0

yea i was not sure about that so i doubt myself thanks alot anyways

- #10

- 423

- 2

You're welcome. If you aren't sure drawing a diagram is usually helpful.

- #11

- 1

- 0

I though i know this well but i don't even know how to set this up

initial speed is zero..since it is at rest before hitting...after hitting it will move with speed 44.271 m/s

Share: