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## Homework Statement

A tennis ball is thrown from ground level with velocity vo directed sin 30 above the horizontal. If it takes the ball 1.0s to reach the top of its trajectory, what is the magnitude of the initial velocity?

## Homework Equations

The initial vertical component of velocity is

(1) Vy,o = Vo sin(30)

As the ball rises gravity slows the ball down until the vertical

velocity is zero. The equation that describes the vertical component

of velocity as a function of time is

(2) Vy = Vy,o - gt

Where g = 9.8m/s^2 is the magnitude of the acceleration due to

gravity and t is time. Now when t = 1s Vy = 0 (this corresponds

to the maximum height) so we have.

(3) 0 = Vy,o -g(1s)

Substituting (1) and g = 9.8m/s^2 into (3) gives

(4) 0 = Vo sin(30) - 9.8 m/s

solving for Vo

(5) Vo = (9.8 m/s)/ sin(30)

= (9.8 m/s)/ 0.5

= 19.6 m/s

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* Vo = 19.6 m/s *

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## The Attempt at a Solution

**Why am I using sin 30 - I understand that that is the y direction, but why is it not**

0 = Vo - 9.8 (1)

Vo = -9.8, I understand this answer is not reasonable but I want to know the explanation for why I am using sin 30. I hope you understand what I am asking :)

0 = Vo - 9.8 (1)

Vo = -9.8, I understand this answer is not reasonable but I want to know the explanation for why I am using sin 30. I hope you understand what I am asking :)