1. The problem statement, all variables and given/known data A sniper barrel is exactly one meter above the ground and perfectly horizontal. 1000m away is a target one meter above the ground. if the bullet leaves the gun with a muzzle velocity of 1500m/s will it reach the target? (no, next part is my problem) at what angle should the sniper shoot to hit the target? [tex]\Delta[/tex]x = 1000m [tex]\Delta[/tex]y = 0m ax = 0 ay = -9.8m/s2 (gravity) V0x = ? V0y = ? time (t) = ? angle [tex]\theta[/tex] = ? V0 = 1500m/s 2. Relevant equations [tex]\Delta[/tex]X = v*t [tex]\Delta[/tex]V = V - V0 = a*t [tex]\Delta[/tex]X = (1/2)*a*t2 + V0*t V2 = 2*a*[tex]\Delta[/tex]X - V02 V0x = V0*cos[tex]\Theta[/tex] V0y = V0*sin[tex]\Theta[/tex] *the first four equations can be used for either the X or Y dimension; [tex]\Delta[/tex]X will just change to [tex]\Delta[/tex]Y 3. The attempt at a solution I'm not looking for the answer, just a point in the right direction please. For part one of the question, I found that it would take the bullet 2/3 of a second to reach the target in the X dimension. But in that same time, it would fall 2.2m, hitting the ground 322.3m from the target.