1. The problem statement, all variables and given/known data A stone thrown horizontally from a height of 6.02m hits the ground at a distance of 13.90m. Calculate the initial speed of the stone. Neglect air resistance. 2. Relevant equations 1. v = v0 + at 2. x = x0 + (1/2)(v0+v)t 3. x = x0 + v0t + (1/2)at^2 4. v^2 = v0^2 + 2a(x-x0) 3. The attempt at a solution First I solved for t using the y components of equation 3. So 0 = x0y + (1/2)at^2; a = -g; x0y = 6.02; so t = 1.23s Then using x components of equation 2 I said v0x = vx; 13.9 = v(1.23); so v = 11.3 m/s but that's not the right answer. Sorry this isn't more clear, I'm in a hurry. Thanks.