A projectile is shot from the edge of a vertical cliff 60.0meters above the ocean. It has a speed of 100m/s and is fired at an angle of 35 degrees above horizontal. How far from the foot of the vertical cliff does the projectile land.
Yf= Yinitial + ViT + 1/2 aT^2
The Attempt at a Solution
Ok so I can solve this problem but what really confuses me is why I can't solve for T using Y= Yinitial + ViT + 1/2 aT^2. I think they give us all the variables to solve it this way.
Yf = 0, Y initial = 60, Vi = 57.4, a = -9.8m/s^2
So I set it up like, 0=60+57.4T-4.9t^2
From there I factor out a T, -60=t(57.4- 4.9t)
t= -117, -/ 4.9= t
(I assume we lose possible solutions if I factor out the T, so instead I have to use the quadratic formula? Not sure though)
And just a random question, Does anyone know where they gave a bunch of 2d kinematic examples and ones regarding force? I've been looking all day but can't really find a bunch of examples for practice. Thanks guys!