1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

2D Kinematics

  1. Feb 24, 2004 #1
    Hey Guys
    (sorry about other post in diff topic i never saw this one)
    Here is the physics problem im having problems with.

    1)A .50 kg ball is thrown at 42 degrees above the horizontal at 19 m/s from a stationary hot air baloon 25m above the ground. What is the range?

    ps Any general information on 2d kinomatics would be greatly appreciated. im having trouble grasping the concepts in this chapter.

  2. jcsd
  3. Feb 24, 2004 #2

    Chi Meson

    User Avatar
    Science Advisor
    Homework Helper

    THis is a standard projectile motion problem. The "range" refers to the horizontal displacement, that is, the distance along the ground from a point directly underneath the balloon to the point where the ball lands.

    We assume that air resistance is ignorable, so the mass of the ball is not important.

    The time that the ball is in the air depends only on the vertical componants. So find the vertical component of the initial velocity. Since it goes up at first call this initial velocity positive.

    The vertical displacement is the height of the balloon but since it ends up below the starting point, the vertical displacement is a negative value (it does not matter that the ball goes up higher before falling, the displacemnt only cares about the difference between the initial and final positions.

    The vertical acceleration is -9.80 m/s^2 of course.

    use the formula d=vt + 1/2 a t^2 and solve for t. This means you use the quadratic equation to find t. YOu get two answers, but only one will be positive. (Watch all the negative values, they are all important)

    After you find the time of the flight, multiply this time by the horizontal component of the initial velocity. Since horizontal motion is not accelerated, d=vt. The d is your answer.
  4. Feb 24, 2004 #3

    Chi Meson

    User Avatar
    Science Advisor
    Homework Helper

    Hey, Where's my million?
  5. Feb 24, 2004 #4
    THX MAN thats exactly how its suppose to be done to you guys are great!! Heres your million.

    1 000 000
  6. Feb 25, 2004 #5

    Chi Meson

    User Avatar
    Science Advisor
    Homework Helper

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: 2D Kinematics
  1. Kinematics in 2D (Replies: 1)

  2. 2D kinematic (Replies: 10)

  3. 2D Kinematics (Replies: 2)

  4. 2D Kinematics (Replies: 2)

  5. 2d kinematics (Replies: 7)