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## Homework Statement

A rocket is launched at an angle of 75 degrees and accelerates at 21.4 m/s^2. Where is the rocket located (from the point of origin) after 11.2 seconds?

## Homework Equations

a=(vf - vi) / t

(vf + vi) / 2 = (xf - xi) / t

where: vf = velocity final, vi = velocity initial, xf = displacement final, xi = displacement initial, and of course a = acceleration and t = time

## The Attempt at a Solution

*given solution: Xfx = 353.7 m; Xfy = 693.4 m (don’t forget gravity in the y-direction)*

__X__

ax = 21.4cos75 = 5.54

vix = vi cos75

vfx= vi cos75

xfx = ?

xix = 0

t = 11.2

__Y__

ay = 21.4sin75 = 20.67

viy = vi sin75

viy = ?

xfy = ?

xiy = 0

t = 11.2

any one got any Ideas to the path to the solution, and how do i account for gravity? add/subtract?

thanks