1. The problem statement, all variables and given/known data A speaker system is suspended by the cables attached at and . The mass of the speaker system is 92.5kg, and its weight acts at G. Determine the tensions in the cables hanging from (a)D and (b)E . 2. Relevant equations [tex]\sum[/tex]M=0 [tex]\sum[/tex]F=0 3. The attempt at a solution First, I decided to find reactions at C. I drew the arrows on the diagram, where the horizontal one going to C is Cx and vertical one is Cy. Vertical arrow pointing to A will be further referred to as Ay. So I got: Mc=Mcdue to A+Mcdue to G=0 Mcdue to A=92.5*9.81*1.5 Ay * 1 = 1361.14N Since the moment is positive, Ay has to be pointing downwards Thus Ay (vector)=-1361.14N. From this, we can find Cy: [tex]\sum[/tex]Fy = -1361.14N+Cy-907.425N=0 so Cy=2269 There are no x-direction forces, so Cx=0 Now that we know reactions at C, we can "cut" the cables (E&D) and find E using moment around D: MD=+(1.5)*(1361.14)-2269*(.5)-(1)(0) - E*1.5=0 From which E (vector)=-604.81 Then we can use E, to find D: Sum of Fy = -1361.14+2269-604.81+D=0 D=-303.05 Is that right? Or have I made some wrong assumptions? Also, I got negative numbers for E and D because they're forces that are acting down. But how would I put in the answer? Tension should be positive 'cause it's just a magnitude, right? Thanks!