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2D Momentum Problem

  1. Oct 24, 2012 #1
    1. The problem statement, all variables and given/known data
    The stoplight had just changed and a 2000 kg Cadillac had entered the intersection, heading north at 3.0 m/s, when it was struck by a 1000 kg eastbound Volkswagen. The cars struck together and slid to a half, leaving skid marks angled 35 degrees north of east. How fast was the Volkswagen going just before the impact?


    2. Relevant equations



    3. The attempt at a solution
    So basically what I did was divided into components.

    x: (3)(2000) = (3000)*v_x
    y: (v_vw)*(10000) = (3000)*v_y

    v_x, v_y is the velocity (after collision) in the x and y direction, respectively, of both cars stuck together (since it is an inelastic collision).
    v_vw is the initial velocity of the Volkswagen.

    Now what I did was that the angle is 35 degrees north of east. So basically made a triangle and figured that tan(35) = (v_y)/(v_x). This means (v_x)*(tan35) = v_y.

    Then, I simplified the component equations to get:
    x: 2 = v_x
    y: v_vw = 3*v_y

    Then plugging in for v_y, I got: v_vw = 3(2)(tan35) = 4.2 m/s as the velocity of the volkswagen.

    However, the answer key says 8.6 m/s. Could someone please help me out?


    Thanks
     
  2. jcsd
  3. Oct 24, 2012 #2

    ehild

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    Homework Helper
    Gold Member

    What directions you call x and y?

    ehild
     
  4. Oct 24, 2012 #3
    Thanks!!

    I got it now, I should have drawn a reference frame with the axis or maybe I should have used the actual coordinate axis.

    tan 35 = (v_x)/(v_y)
    (v_y) = (v_x)/tan35

    v_vw = 3*v_y = 3*2/tan35 = 6/tan35 = 8.6

    Thanks again.
     
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