1. The problem statement, all variables and given/known data A 42.5kg person is going down a hill sloped at 42.0 degrees. The coefficient of kinetic friction between the snow and skis is 0.180. How fast is the skier going 4.56 seconds after starting from rest? 2. Relevant equations Is ffkmax equal to net force? 3. The attempt at a solution coefficient of kinetic friction:.180 t=4.56 mass=42.5kh Angle=42 degrees Vo=0 I created a free body diagram. I used (mg)(cos 42) to get total force going opposite of FN. I made that force equal to FN and plugged the number into the equation ffkmax=coefficient(.180)*FN(315.83). Got 76.5N=ffkmax. Now im not sure if i use fnet=ma or a motion equation.